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-4x^2+110x+294=0
a = -4; b = 110; c = +294;
Δ = b2-4ac
Δ = 1102-4·(-4)·294
Δ = 16804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16804}=\sqrt{4*4201}=\sqrt{4}*\sqrt{4201}=2\sqrt{4201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{4201}}{2*-4}=\frac{-110-2\sqrt{4201}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{4201}}{2*-4}=\frac{-110+2\sqrt{4201}}{-8} $
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